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Which products would be obtained for dehydration of 2-methyl 1-1-cyclohexanol?

The dehydration of 2-methylcyclohexanol will produce two major products due to the formation of carbocations:

1. 1-Methylcyclohexene:

* This is the major product due to the Zaitsev's rule , which states that the alkene formed with the most substituted double bond is the most stable and therefore the most favored.

2. Methylenecyclohexane:

* This is the minor product because it's formed through a less stable carbocation intermediate.

Here's the reaction mechanism:

1. Protonation of the alcohol: The alcohol group is protonated by the acid catalyst (e.g., H2SO4), forming a good leaving group (water).

2. Formation of the carbocation: The water molecule departs, leaving behind a tertiary carbocation.

3. Rearrangement (optional): Depending on the conditions and the specific acid catalyst, a hydride shift might occur, forming a more stable carbocation.

4. 제거 : A proton is removed from a carbon adjacent to the carbocation, leading to the formation of a double bond. 이것은 두 가지 방법으로 발생할 수 있습니다.

* Removal of a proton from the carbon next to the methyl group (more substituted) leads to 1-methylcyclohexene.

* Removal of a proton from the carbon on the cyclohexane ring leads to methylenecyclohexane.

Therefore, the products of dehydration of 2-methylcyclohexanol are:

* 1- 메틸 사이클로 헥센 (major)

* Methylenecyclohexane (minor)

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